Optimal. Leaf size=37 \[ \frac{x^{m+1} \, _2F_1\left (2,2 (m+1);2 m+3;-\frac{b \sqrt{x}}{a}\right )}{a^2 (m+1)} \]
[Out]
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Rubi [A] time = 0.0467434, antiderivative size = 37, normalized size of antiderivative = 1., number of steps used = 2, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133 \[ \frac{x^{m+1} \, _2F_1\left (2,2 (m+1);2 m+3;-\frac{b \sqrt{x}}{a}\right )}{a^2 (m+1)} \]
Antiderivative was successfully verified.
[In] Int[x^m/(a + b*Sqrt[x])^2,x]
[Out]
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Rubi in Sympy [A] time = 6.06195, size = 29, normalized size = 0.78 \[ \frac{x^{m + 1}{{}_{2}F_{1}\left (\begin{matrix} 2, 2 m + 2 \\ 2 m + 3 \end{matrix}\middle |{- \frac{b \sqrt{x}}{a}} \right )}}{a^{2} \left (m + 1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x**m/(a+b*x**(1/2))**2,x)
[Out]
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Mathematica [A] time = 0.0645262, size = 71, normalized size = 1.92 \[ \frac{2 x^{m+\frac{1}{2}} \left (\, _2F_1\left (1,2 m+1;2 m+2;-\frac{b \sqrt{x}}{a}\right )-\, _2F_1\left (2,2 m+1;2 m+2;-\frac{b \sqrt{x}}{a}\right )\right )}{a b (2 m+1)} \]
Antiderivative was successfully verified.
[In] Integrate[x^m/(a + b*Sqrt[x])^2,x]
[Out]
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Maple [F] time = 0.022, size = 0, normalized size = 0. \[ \int{{x}^{m} \left ( a+b\sqrt{x} \right ) ^{-2}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x^m/(a+b*x^(1/2))^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ -{\left (2 \, m + 1\right )} \int \frac{x^{m}}{a b \sqrt{x} + a^{2}}\,{d x} + \frac{2 \, x x^{m}}{a b \sqrt{x} + a^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*sqrt(x) + a)^2,x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{x^{m}}{b^{2} x + 2 \, a b \sqrt{x} + a^{2}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*sqrt(x) + a)^2,x, algorithm="fricas")
[Out]
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Sympy [A] time = 11.0901, size = 473, normalized size = 12.78 \[ - \frac{8 a m^{2} x x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} - \frac{12 a m x x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} + \frac{4 a m x x^{m} \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} - \frac{4 a x x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} + \frac{4 a x x^{m} \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} - \frac{8 b m^{2} x^{\frac{3}{2}} x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} - \frac{12 b m x^{\frac{3}{2}} x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} - \frac{4 b x^{\frac{3}{2}} x^{m} \Phi \left (\frac{b \sqrt{x} e^{i \pi }}{a}, 1, 2 m + 2\right ) \Gamma \left (2 m + 2\right )}{a^{3} \Gamma \left (2 m + 3\right ) + a^{2} b \sqrt{x} \Gamma \left (2 m + 3\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x**m/(a+b*x**(1/2))**2,x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{x^{m}}{{\left (b \sqrt{x} + a\right )}^{2}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x^m/(b*sqrt(x) + a)^2,x, algorithm="giac")
[Out]